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Gwar [14]
3 years ago
6

Find to the nearest degree, the measure of the smaller acute angle of a right triangle whose sides are 7, 24,

Mathematics
1 answer:
Semmy [17]3 years ago
7 0
The smallest angle would be 16.26°, with the other angles being 90° & 73.74°
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Solve (t-5) = 2 where t is a real number.<br> Simplify your answer as much as possible.
In-s [12.5K]

Answer:

7

Step-by-step explanation:

T-5=2 2+5=7

7 0
4 years ago
What is 25 more than n in an algebraic expression
sashaice [31]
25 + n
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8 0
3 years ago
What is the height of this triangle?
zavuch27 [327]

Answer:

XY (height) is approximately 20.8 feet

Step-by-step explanation:

let h = XY

tan60° = h/12

h = 12·tan60°

h = 20.78 ft

3 0
3 years ago
Use the function f(x) to answer the questions.
frutty [35]

<u>Part A</u>

<u />-16x^2 + 60x+16=0\\\\4x^2 - 15x-4=0\\\\(4x+1)(x-4)=0\\\\x=-\frac{1}{4}, 4

<u>Part B</u>

The vertex of the graph will be a maximum because the leading coefficient is negative.

The x coordinate of the vertex is -\frac{60}{2(-16)}=\frac{15}{8}.

When x=15/8, f\left(\frac{15}{8} \right)=\frac{289}{4}.

So, the vertex has coordinates \left(\frac{15}{8}, \frac{289}{4} \right)

<u>Part C</u>

Plot the two x-intercepts and the vertex and then draw a curve in the shape of a parabola passing through them.

The graph is in the attached image.

3 0
2 years ago
Read 2 more answers
Q5 Q6.) Find the exact value of the six trigonometric functions of theta.
lilavasa [31]
5y - 2x + 1 = 0.
5y = 2x-1.

y = 2/5 x - 2/5

this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)


tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2



5 0
4 years ago
Read 2 more answers
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