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Ksenya-84 [330]
3 years ago
7

Someone please help me in math

Mathematics
2 answers:
N76 [4]3 years ago
8 0
Hope this helps out !!!!

Viktor [21]3 years ago
5 0
3x-y=4
2x+y=6

Add the two equations together:
5x=10
x=2

Plug 2 for x into the second equation:
2(2)+y=6
4+y=6
y=2

The solution is (2,2)
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Simplify the expression.
Nimfa-mama [501]
The answer is C.15c+72
5 0
3 years ago
A rickshaw company counted 39 ticket receipts last week. The price for a weekday ticket is $7, and the price for a weekend ticke
Mademuasel [1]

Answer:

x+y = 39 and 14y+19=666

Step-by-step explanation:

Let x is the no of tickets for the weekend and y for the weekday.

The price for a weekday ticket is $7, and the price for a weekend ticket is $9.50. The rickshaw driver collected a total of $333 for the week.

Equation (1) should be :

x+y = 39 (because a rickshaw company counted 39 ticket receipts last week)

Equation (b) should be :

7y+9.5=333

Multiplying both sides by 2.

14y+19=666

Hence, the two equations that represent the situation are :

x+y = 39 and 14y+19=666

3 0
3 years ago
Bonnie ran a total of 18 miles over the course of 2 track practices. How many miles would Bonnie have run after 7 track practice
Verdich [7]

Answer:

63 miles

Step-by-step explanation:

Bonnie ran a total of 18 miles over the course of 2 track practices. How many miles would Bonnie have run after 7 track practices?

2 track practices = 18 miles

7 track practices = y miles

Cross Multiply

2 track practices × y miles = 18 miles × 7 track practices

y miles = 18 miles × 7 track practices/ 2 track practices

y miles = 63 miles.

Therefore, Bonnie will have run 63 miles after 7 track practices

6 0
3 years ago
Is the function f(x)=(−13)x an exponential function? If so, identify the base. If not, why not?
Leto [7]
The answer is C because there is no number raised to the power of x in the equation
7 0
3 years ago
H(x) = x3 - 64x2. Determine the average rate of change of the function between x = -2 and x = 0
Marysya12 [62]
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
\textit{average rate}\\
\textit{ of change}
\end{array}
\\\\\\
H(x)=x^3-64x^2\quad 
\begin{cases}
x_1=-2\\
x_2=0
\end{cases}\implies \cfrac{H(x_2)-H(x_1)}{x_2-x_1}
7 0
3 years ago
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