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jarptica [38.1K]
4 years ago
12

Questions 2-7 will all be in regards to this data set:Observation X Y1 20 302 23 353 28 404 26 385 24 376 32 457 35 508 24 349 3

1 4210 23 32What is the Pearson's coefficient of correlation for the data set above?

Mathematics
1 answer:
Tomtit [17]4 years ago
3 0

Answer:

r =0.4437

Step-by-step explanation:

We have the follwoing dataset:

X: 20,23,53,4,24,32,35,24,31,23

Y: 30,35,40,38,37,45,50,34,42,32

n=10

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 269, \sum y = 383, \sum xy = 10609, \sum x^2 =8645, \sum y^2 =15007  

Th excel figure attached shows the calculations for each sum.

r=\frac{10(10609)-(269)(383)}{\sqrt{[10(8645) -(269)^2][10(15007) -(383)^2]}}=0.4437  

So then the correlation coefficient would be r =0.4437

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