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Delvig [45]
3 years ago
13

What is each expression written using each base only once? 8 ^ 8 x 8 ^ 4

Mathematics
2 answers:
Lelechka [254]3 years ago
8 0

Answer:

Option (d) is correct.

The given expression  8^8 \times 8^4 using base only once is 8^{12}

Step-by-step explanation:

Given expression 8^8 \times 8^4

We have to write the given expression using each base only once.

Consider the given expression  8^8 \times 8^4

We know, property of exponents, a^n\times a^m=a^{m+n}

Using the above property we have,

8^8 \times 8^4=8^{8+4}

Thus, simplify , we get,

8^8 \times 8^4=8^{12}

Thus, option (d) is correct.

The given expression  8^8 \times 8^4  using base only once is 8^{12}

OlgaM077 [116]3 years ago
5 0
D! When base numbers are being multiplied, you add the exponents. So 8 + 4 would be 12.
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Calculations:
Sophie:
$330(1+4%*2)
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4 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

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