answer is hcbiurrcuiehdieuhideidehdue -12y+48
Answer: The probability is 0.5136.
To find this probability we have to find the range of the values on the normal distribution table.
First, we need to find the percent for each making z-score.
Lower end: 50/24 = 2.08 = 0.0183
Upper end: 2/24 = 0.08 = 0.5319
Now, that we have the upper and lower ends, we can subtract them to find the difference or the range.
0.5319 - 0.0183 = 0.5136
There is a 51.36% chance they are in the given range.
Answer:
t = 0.7
Step-by-step explanation:
s = k/t where 'k' is the constant of variation
given: 0.5 = k/7 so k = 3.5
5 = 3.5/t
5t = 3.5
t = 0.7
The system of equations when been placed in a matrix yields
![\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%26-1%5C%5C120%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-175%5C%5C25080%5Cend%7Barray%7D%5Cright%5D)
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the equation:
y = 650x + 175 and;
y = 25080 - 120x
Rearranging the equations gives:
650x - y = -175 and;
120x + y = 25080
Placing the equations in a matrix gives:
![\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%26-1%5C%5C120%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-175%5C%5C25080%5Cend%7Barray%7D%5Cright%5D)
The system of equations when been placed in a matrix yields
![\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%26-1%5C%5C120%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-175%5C%5C25080%5Cend%7Barray%7D%5Cright%5D)
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer:
The answer to your question is 116.53 ft
Step-by-step explanation:
Data
length = 29 ft
width = 21 ft
π = 3.14
Process
1.- Calculate perimeter of the rectangle and subtract 1 length
Perimeter of the rectangle = 2l + 2w - l
Perimeter of the rectangle = 2(29) + 2(21) - 29
= 58 + 42 - 29
= 71 ft
2.- Calculate the perimeter of a semicircle
Perimeter = 2πr/2 = πr
radius = r = 29/2
= 14.5 ft
Perimeter = (3.14)(14.5)
= 45.53 ft
3.- Calculate the total length of the fence
fence = 45.53 + 71
= 116.53 ft