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3 years ago

In the right triangle shown, m

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

8 0

Where is it though...

Dafna1 [17]3 years ago

3 0

Answer:4 root 3

Step-by-step explanation:

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Entrance to a state park costs $6 per vehicle plus $2 per person in the vehicle how much would it cost for a car with 2 people t

Igoryamba

Answer:

car with 2 people: $10

car with 4 people: $14

car with 10 people: $26

Step-by-step explanation:

6 0

3 years ago

Eighteen increased by the product of three times a number w is 30. Find the number.

faltersainse [42]

Answer:

w=4

Step-by-step explanation:

18+3w=30

3w=30-18

3w=12

w=4

6 0

4 years ago

Read 2 more answers

7/8 - 1/4 - 1/2= ??

madreJ [45]

Step-by-step explanation:

We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.

Cheers!

7 0

2 years ago

Select the correct answer. I'll mark brainiest, thank you!

Virty [35]

Answer:

C is your answer.

Step-by-step explanation:

Hope this helps.

8 0

3 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago