When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
A) 25
B) 64
Step-by-step explanation:
Hope this helps :))
Answer:
No answer just clues
Step-by-step explanation:
x/100*160/1=185/1
y/100*56/1=77/1
I just can't do anymore metal math today, sorry.
Answer:
The students where asleep and did not have phones turned on.
Step-by-step explanation: