Answer:143.75
Step-by-step explanation:
125 x .15 =18.75 and add
Answer:
A) The minimum required diameter of the brass shaft D₁ = 0.00176 m
B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m
Step-by-step explanation:
<u>Data:</u>
A compound shaft has two segments made of brass and aluminium
Allowable shear stress of Brass = 69 MPa.
allowable sheer stress of Aluminium = 86 MPa.
Torque TC = 23900 N-m
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<u>Find</u>: Minimum required diameter of the brass D₁ and Auminium D₂
<u>Solution</u>: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.
Answer:
the third graph is correct
Step-by-step explanation:
edge
the second part is x<1
The first term is -2. The fourth term is -16. And the last term is -256.
To find them, lets say the first term, replace n with 1. You can use this idea to find out the rest (which I've already done, but just to explain to you.).
Answer:
if it is multiple choice it's a bc I am on the same thing