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stiv31 [10]
3 years ago
9

What is the reflection of an object referred to? post-image image transformation pre-image

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer: image transformations

Step-by-step explanation:

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How many ounces of gold are in a 16​-karat gold chain that weighs 2.6 ​ounces?
oksano4ka [1.4K]

A 16 karat gold means that there are 16 parts of gold in 24 parts of the gold chain. Therefore the weight of the pure gold is:

pure gold = (16 / 24) * 2.6 ounces

<span>pure gold = 1.73 ounces</span>

7 0
3 years ago
If someone was born in 2018 September 12th how old will they be in 2082?
Margaret [11]

Answer: 64 years old

Step-by-step explanation:You subtract 2082 by 2018 to get the sum of 64

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Read 2 more answers
PLEASE HELP WITH THESE 4 PROBLEMS
Marizza181 [45]

Answer:

  • y = -5/2x + 5
  • y = 2x -1
  • y = 24/11
  • y = 4x + 4

Step-by-step explanation:

To solve for y, subtract the x-term and divide by the coefficient of y.

5x +2y = 10

  2y = -5x +10

  y = -5/2x + 5

__

2y -4x = -2

  2y = 4x -2

  y = 2x -1

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7y +4y = 24

  y = 24/11

We assume there is a typo, but cannot tell what it is. Use the same method as described and demonstrated for the other problems.

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-2x +1/2y = 2

  1/2y = 2x +2

  y = 4x +4

8 0
3 years ago
What’s the domain and range for these two?
user100 [1]

Step-by-step explanation:

1) the domain is from -3 to 5 D [-3,5]

the range is from -5 to -2. R [-5,-2]

2)the domain is from -3 to 6 but not including 6 D [-3,6)

the range is from -5 but not including -5 to 2. R (-5,2]

4 0
3 years ago
Please help with the question in the picture!
Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

<u>METHOD - I</u>

<u><em>Sin² C + Cos² C = 1</em></u>

Cos² C = 1 - Sin² C

Cos² C = 1 - \frac{9}{25}

Cos² C = \frac{25 - 9}{25}

Cos² C = \frac{16}{25}

Cos C = \sqrt{\frac{16}{25} }

Cos C = \frac{4}{5}

As we know that

Tan C = \frac{Sin C}{Cos C }

<em>Tan C = \frac{\frac{3}{5} }{\frac{4}{5} }</em>

<em>Tan C = \frac{3}{4}</em>

<u>METHOD - II</u>

Given Sin C = \frac{3}{5} = \frac{Height}{Hypotenuse}

therefore,  

AB ( Height ) = 3; BC ( Hypotenuse) = 5

<em>∵ ΔABC is Right triangle.</em>

<em>∴ By Pythagorean Theorem-</em>

<em>AB² + AC² = BC²</em>

<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>

<em>AC² = 5² - 3²</em>

<em>AC² = 25 - 9</em>

<em>AC² = 16</em>

<em>AC  ( Base) = 4</em>

<em>Since, </em>

<em>Tan C = \frac{Height}{Base}</em>

<em>Tan C = \frac{AB}{AC}</em>

<em>Hence Tan C = \frac{3}{4}</em>

<em />

4 0
3 years ago
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