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Vlad1618 [11]
4 years ago
9

As a motorcycle accelerates at 5.1 m/s2, its speed changes from 16 km/h to 118 km/h. How long does this take?

Mathematics
2 answers:
ser-zykov [4K]4 years ago
8 0
<em>Acceleration (a) = 5.1 m/s</em>²
<em>Initial speed (u) = 16 km/h </em>⇒ \frac{16*1000}{3600} <em>m/s </em>≈ <em>4.5m/s</em><em>
</em>
<em>Final speed (v) =118 km/h </em>⇒ \frac{118*1000}{3600} <em>m/s</em> ≈ <em>32.8m/s</em><em>
</em>

Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS

<em>So, When all quantities are in S.I. unit then,
</em>
putting the values in the equation of motion,

<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>\frac{ v^{2} - u^{2} }{2a}
Putting values in derived equation,
⇒ <em>S = </em>\frac{ (32.8)^{2} - (4.5)^{2} }{2*(5.1)}
⇒ <em>S = </em>\frac{ 1075.84 - 20.25}{10.2}
⇒ <em>S = </em>\frac{1055.59}{10.2}
⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em><em>
The total distance covered in that given condition is approx. 103.289 m.</em>
zysi [14]4 years ago
3 0

it takes 5.6 s

hope this helped

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