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3 years ago

7.6375 correct to 2 d.p.

1 answer:

5 0

7.6375 =

1 Decimal Place = 7.6
2 Decimal Place = 7.64
3 Decimal Place = 7.638
4 Decimal Place = 7.6375

So the answer is 7.64 .
The 3 rounds up because 7 is bigger than 5...

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Sara is reading a 280-page book. If

fenix001 [56]

Answer:

129 - 280 = 51.. So the answer is 51%

7 0

3 years ago

A video game arcade offers a yearly membership with reduced rates for game play. A single membership costs $60 per year. Game to

Nastasia [14]

Let

x-------> the number of game tokens purchased for a member of the arcade

y-------> the function of the yearly cost in dollars

we know that

the function y of the yearly cost in dollars is equal to

$y =\frac{1}{10} x +60$

This is the equation of the line

using a graph tool

see the attached figure

Statements

case a) The slope of the function is $1.00

The statement is False

The slope of the function is equal to $\frac{1}{10} \frac{\$}{tokens}$

case b) The y-intercept of the function is $60

The statement is True

we know that

The y-intercept of the function is the value of the function when the value of x is equal to zero

for $x=0$

$y =\frac{1}{10}*0 +60$

$y =\$60$

case c) The function can be represented by the equation y =(1/10)x + 60

The statement is True

The equation of the function is equal to $y =\frac{1}{10} x +60$

case d) The domain is all real numbers

The statement is False

The value of x cannot be negative, therefore the domain is the interval

[0,∞)

case e) The range is {y| y ≥ 60}

The statement is True

The range of the function is the interval-------> [60,∞)

see the attached figure

8 0

3 years ago

Read 2 more answers

Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0

3 years ago

Which of the following is a solution of y> lXI - 6?

xeze [42]

Answer:

Step-by-step explanation:

if you plug the coordinates into the function it is correct unlike the other options

4 0

3 years ago

А)

Nookie1986 [14]

Answer:

Step-by-step explanation:

surface area of sphere=a

4pir^2=a

r^2=a/4p

r=root(a/4pi)

if radius is doubled

r1=2root(a/4pi)

r1^2=4(a/4pi)

a/a1=(4pia/4pi)/(4pi 4a/4pi)=1/4

so a is increased by 4 times

6 0

2 years ago