Answer:
1 1/2
Hope that helps!
Step-by-step explanation:
Sum means to Add.
So the sum of d and 9 would be d + 9
Answer:
A bit of a doosy, but bare with me: f*g*h(x) = 
Step-by-step explanation:
So explaining this is a bit awkward as well, but I can try...So
Starting from g(x) working that backwards into f(x), so...
g(x) = 
f(x) = 
Take your g(x) and plug it into your f(x) into every x you see
f(g(x)) = 
~ I hope you can visualize this, but do you see how g(x) plugs into f(x)...
Now you still have one more step which you still need to include h(x), so
Remember h(x) = 
Now plug in your h(x) into every x you see from f(g(x)) and it should look like...
It takes value from a user and then user the operation of (+,-,*/).
i used c++ programming language to solve this program:
#include<iostream>
using namespace std;
int main() {
int var1, var2;
char operation;
cout << "Enter the first number : ";
cin >> var1;
cout << endl;
cout <<"Enter the operation to be perfomed : ";
cin >> operation;
cout << endl;
cout << "Enter the second nuber : ";
cin >> var2;
cout << endl;
bool right_input = false;
if (operation == '+') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 + var2);
right_input = true;
}
if (operation == '-') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '*') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 * var2);
right_input = true;
}
if (operation == '/' && var2 != 0) {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '/' && var2 == 0) {
cout << "Error. Division by zero.";
right_input = true;
}
if (!right_input) {
cout << var1 << " " << operation << " " << var2 << " = " << "Error;";
cout << "Invalid Operation!";
}
cout << endl;
system("pause");
return 0;
}
