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4 years ago

13

william earns $13,644.80 per year, and has his federal taxes withheld from each weekly check. In addition, total of $53.60 is de

ducted from each check for Social Security and Medicare. How much is his net pay for each weekly check?

1 answer:

Gala2k [10]4 years ago

5 0

Federal tax rate is 15%net weekly pay = 13644.80/52 * ( 1 - .15) - 53.60 = $169.44

Hope this helps :)

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If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

<h3 /><h3>----------------------------------------------------------------------------------------------------</h3>

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

<h3>----------------------------------------------------------------------------------------------------</h3>

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

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3 years ago

Edgar is getting better at math. On his first quiz he scored 57 points, then he scores 61 and 65 on his next two quizzes. If his

mario62 [17]

Answer:

His score is increasing by four each time, so on his 9th quiz, his score will be 89

hope that helps!

Step-by-step explanation:

4 0

4 years ago

Select all the expressions that are equivalent to 15n - 10

jolli1 [7]

What r the expressions

8 0

3 years ago

Read 2 more answers

Triangle ABC has vertices A(–2, –3), B(–5, –3), and C(–4, –2). The triangle is rotated 90° counterclockwise around the origin.

Mama L [17]

The answer is the option B: A'(3, -2), B'(3, -5), C'(2, -4).

The explanation is shown below:

1. You must apply the following rule of rotation when the figure is rotated 90° counterclockwise around the origin:

$(x,y)$ → $(-y,x)$

2. Then, as you can see, you must switch $x$ and $y$ and multiply $y$ by -1.

3. Keeping this on mind, you have that the vertices of the triangle A'B'C' are the following:

A(-2,-3)→A'(3,-2)

B(-5,-3)→B'(3,-5)

C(-4,-2)→C(2,-4)

4. Therefore, you can conclude that the answer is the option B.

4 0

3 years ago

Read 2 more answers

In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence

Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of <em>z</em> for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0

3 years ago