Triangle ABC has vertices A(–2, –3), B(–5, –3), and C(–4, –2). The triangle is rotated 90° counterclockwise around the origin.
2 answers:
The answer is the option B: A'(3, -2), B'(3, -5), C'(2, -4).
The explanation is shown below:
1. You must apply the following rule of rotation when the figure is rotated 90° counterclockwise around the origin:
→
2. Then, as you can see, you must switch and
and multiply
by -1.
3. Keeping this on mind, you have that the vertices of the triangle A'B'C' are the following:
A(-2,-3)→A'(3,-2)
B(-5,-3)→B'(3,-5)
C(-4,-2)→C(2,-4)
4. Therefore, you can conclude that the answer is the option B.
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Answer: 2
Step-by-step explanation:
Recall from the laws of Logarithms:
Log a - Log b = Log ( a/b )
That means
Log 200 - Log 2 = Log ( 200/2)
= Log 100 , which could be written as
Log
Recall from laws of Logarithms:
Log = b Log a
Therefore:
Log = 2 Log 10
Also from law of Logarithm
Log 10 = 1
Therefore 2 Log 10 = 2 x 1
= 2