Question

If cot x = .42 and sin x = .92, what is cos x?

Answer 1

$\cot x=\dfrac{\cos x}{\sin x}\\ \cos x=\cot x \sin x\\ \cos x=0.42\cdot0.92=0.3864$

Answer 2

$\cot\alpha=\dfrac{\cos\alpha}{\sin\alpha}\\\\\cot x=0.42;\ \sin x=0.92;\ \cos x=?\\\\subtitute\\\\\dfrac{\cos x}{0.92}=0.42\ \ \ |multiply\ both\ sides\ by\ 0.92\\\\\boxed{\cos x=0.3864\approx0.39}$