Answer: 
Center = (2, 3) radius = 
<u>Step-by-step explanation:</u>
When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:
(x-h)² + (y-k)² = r² where
- (h, k) is the vertex
- r is the radius
1) Group the x's and y's together and move the number to the right side
4x² - 16x + 4y² - 24y = -51
2) Factor out the 4 from the x² and y²
4(x² - 4x ) + 4(y² - 6y ) = -51
3) Complete the square (divide the x and y value by 2 and square it)
![4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2](https://tex.z-dn.net/?f=4%5Bx%5E2-4x%2B%5Cbigg%28%5Cdfrac%7B-4%7D%7B2%7D%5Cbigg%29%5E2%5D%2B4%5By%5E2-6y%2B%5Cbigg%28%5Cdfrac%7B-6%7D%7B2%7D%5Cbigg%29%5E2%5D%3D-51%2B4%5Cbigg%28%5Cdfrac%7B-4%7D%7B2%7D%5Cbigg%29%5E2%2B4%5Cbigg%28%5Cdfrac%7B-6%7D%7B2%7D%5Cbigg%29%5E2)
= 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²
= 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)
= 4(x - 2)² + 4(y - 3)² = -51 + 16 + 36
= 4(x - 2)² + 4(y - 3)² = 1
4) Divide both sides by 4
- (h, k) = (2, 3)
That would be the solution to this
Answer:
draw ka ng teyboll
Step-by-step explanation:
sana maka tulong
Answer:
A. 9 sqrt 2
Explanation:
Plug in hypotenuse and given side into
a^2 + b^2 = c^2 and solve.
<span>a. n/4 ≤ -1
Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.
That in the real number line is all the numbers to the left of - 4 (including -4)
The matching graph is the B.
b. -10n ≥ -100
Divide both sides by - 10 => n ≤ 10
That is all the real numbers less or equal than 10.
In the real number line it is all the numbers to the left of 10, including 10.
So, the matching graph is the A.
c. 5x ≥ 20
Divide both sides by 5 => x ≥ 4
That is all the real numbers greater or equal to 4.
In the real number line it is all the numbers to the right of 4, including 4.
The matching graph is C.</span>
