Set up the given triangle on x-y coordinates with right angle at (0,0). So the two vertices are at (5,0) and (0,2
![sqrt{x} n]{3}](https://tex.z-dn.net/?f=sqrt%7Bx%7D%20n%5D%7B3%7D%20)
)
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>

for a pt (x,y) on line sx+ty=1, the minimum of

equals to

smallest value happens at

so area is

hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
Answer:
y = mx + c
m = -4
at y intercept x = 0
(x,y) =(0,-3)
-3 = -4(0) + c
c = -3
therefore the answer is y = -4x + c
x + 4 = 12 Subtract 4 on both sides to get "x" by itself
x + 4 - 4 = 12 - 4
x = 8
When looking at a rectangular prism, we know that Volume = length * width * height
If we are given that the volume of the prism is 280 cubic meters (m^3), the length is 8 meters, and the width is 7 meters, we can fill in our equation.
280 = 8 * 7 * height
280 = 56 * height
Because we are solving for the height, we divide both sides by 56
280/56 = height
height = 5 meters