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Zigmanuir [339]
1 year ago
6

Find the value of y so that WX is perpendicular to YZ

Mathematics
1 answer:
Alexxandr [17]1 year ago
8 0

step 1

Find out the slope WX

W(2,-3) and X(-4,9)

m=(9+3)/(-4-2)

m=12/-6

m=-2

step 2

Find out the slope YZ

Y(5,y) and Z(-1,1)

m=(1-y)/(-1-5)

m=(1-y)/-6

m=(y-1)/6

step 3

Remember that

If two lines are perpendicular

then

their slopes are negative reciprocal

that means

(y-1)/6=1/2 -----> because the negative reciprocal of -2 is 1/2

solve for y

2y-2=6

2y=6+2

2y=8

<h2>y=4</h2>
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Pls help meeeeeeee I do not understand
Yuki888 [10]

Answer:

960 ft

Step-by-step explanation:

We need to find the surface area. To do this, let's see the shapes that are present. There are two triangles with a base and height of 9 and 12, respectively. There is one rectangle with a base and height of 24 and 15, one with base and height of 24 and 12, and finally one with a base and height of 24 and 9.

The areas are:

Triangles: 1/2bh = 1/2(9)(12) = 48 (there are two of these)

Rectangle 1: bh = (24)(15) = 360

Rectangle 2: bh = (24)(12) = 288

Rectangle 3: bh = (24)(9) = 216

Adding all these areas together, we get 960.

Thus, Monique will need 960 feet of fabric to cover the prism.

Hope this helps!

3 0
3 years ago
MK and ML are tangent to circle J. If MK = 6x – 15 and ML = 2x + 9, find x. * am i right?? * --&gt; provide details if i'm wrong
Veseljchak [2.6K]

Answer:

Step-by-step explanation:

y^{2} = r^{2}  + (4,2)^{2} \\\\ y^{2} - r^{2} = (4,2)^{2} y^{2} =  r^{2} + z^{2} \\\\ y^{2} - r^{2} = z^{2}\\so: z^{2} = (4,2)^{2}  ----> z = 4,2

3 0
3 years ago
Consider the function given by the graph. What are
horrorfan [7]

Answer:

the values of it is the first one. meaning: f(-2)

8 0
3 years ago
Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
3 years ago
Tyler is thinking of a number that is divisible by 2 and by 3. By which of the following numbers must Tyler's number also be div
san4es73 [151]
I think It is 6,12,24,18
5 0
3 years ago
Read 2 more answers
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