Answer:
Expected Value of M is 50 and the Standard Error of M is 3
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation, also called standard error
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
µ = 50 and σ = 18
For the sample
Mean 50 and standard error
.
The answer is:
Expected Value of M is 50 and the Standard Error of M is 3
Answer:
- y = 1.8x +53.7
- 73.5 in 2005
Step-by-step explanation:
The 2-point form of the equation of a line is useful here. It tells you that for the points (x1, y1) and (x2, y2) the line can be written as ...
y = (y2 -y1)/(x2 -x1)(x -x1) + y1
For your given points, this is ...
y = (60.9 -57.3)/(4 -2)(x -2) +57.3
y = 1.8(x -2) +57.3
y = 1.8x +53.7 . . . . . simplify
__
For x = 11 (in 2005), the predicted value is ...
y = 1.8·11 +53.7
y = 73.5