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3 years ago

What is the slope of the line determined by the points (5,-3) and (-9,-6)

Mathematics

1 answer:

Serggg [28]3 years ago

6 0

Answer:

slope = $\frac{3}{14}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (5, - 3) and (x₂, y₂ ) = (- 9, - 6)

m = $\frac{-6+3}{-9-5}$ = $\frac{-3}{-14}$ = $\frac{3}{14}$

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Answer:Angles 1 and 3 are vertical angles

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3 years ago

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OleMash [197]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

(b) (x – 4)^2 + (y – 6)^2 = 16

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2 years ago

Approximately what portion of the box is shaded blue?<br> A.3/5<br> B.2/3<br> C.9/10

BaLLatris [955]

Answer:

I think the answer is C.....

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3 years ago

URGENT MATH HELP BRAINLIEST

Lelechka [254]

Answer:

Step-by-step explanation:

a. This is a right triangle with two sides and one angle given.

-We apply Sine Rule to find the angle B:

$\frac{a}{Sin \ A}=\frac{b}{Sin \ B}=\frac{b}{Sin \ C}$

-The sides given are 10and 17 and the right angle 90°

$\frac{17}{Sin \ 90 \textdegree}=\frac{10}{Sin \ m\angle B}\\\\m\angle B=Sin^{-1}\frac{10}{(17/Sin \ 90\textdegree)}\\\\=36.03\textdegree$

Hence the angle B is 36.03°

b.We again use the sine rule to obtain the unknown angle w:

-15 corresponds to 90° and 9 corresponds to w°

$\frac{a}{Sin \ a}=\frac{b}{Sin \ B}\\\\\frac{15}{Sin \ 90\textdegree}=\frac{9}{Sin \ w\textdegree}\\\\\\\\w=Sin^{-1}(\frac{9}{15}), \ \ Sin \ 90\textdegree=1\\\\=36.87\textdegree$

Hence, the measure of w is 36.87°

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3 years ago