1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dangina [55]
4 years ago
13

3. At a bargain store, Tanya bought 3 items that each cost the same amount. Tony bought 4 items that each cost the same amount,

but each was $2.25 less than the items that Tanya bought. Both Tanya and Tony paid the same amount of money. What was the individual cost of each person's items?
(a) Write an equation. Let x represent the cost of one of Tanya's items.
(b) Solve the equation. Show your work.
(c) Check your solution. Show your work.
(d) State the solution in complete sentences.
Mathematics
1 answer:
Inessa [10]4 years ago
3 0
(a) 3x=4(x-2.25) (or simplified: 3x=4x-9)

(b) 3x=4x-9
0=x-9
x=$9

(c) 3x9=27
4x9=36
36-9=27
and 27=27 therefore they spent the same and it is correct

(d) Tanya's items cost $9 each and Tony's items cost $2.25 less than this, or $6.75
You might be interested in
The heights of twelve month old boys are normally distributed with a mean of 29.8 inches and a standard deviation of 1.2 inches.
Triss [41]

Answer:

About twenty-one percent of twelve month old boys are shorter than 28.8 inches.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.8, \sigma = 1.2

About twenty-one percent of twelve month old boys are shorter than what height?

This is the value of X when Z has a pvalue of 0.21. So it is X when Z = -0.805.

Z = \frac{X - \mu}{\sigma}

-0.805 = \frac{X - 29.8}{1.2}

X - 29.8 = -0.805*1.2

X = 28.8

About twenty-one percent of twelve month old boys are shorter than 28.8 inches.

4 0
4 years ago
The system of linear equations y=2x-1 and y=4x-1 is graphed.
Oksana_A [137]

Answer:

a is the answer and pictured

7 0
4 years ago
Read 2 more answers
Find all Pythagorean triplets of 8.
givi [52]

Answer:

Step-by-step explanation:

There are two Pythagorean Triples containing 8:

6^2+8^2=10^2

8^2+15^2=17^2

4 0
3 years ago
Solve for distributive property <br> -10( x + 9 )
irinina [24]

Answer: -10x - 90

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use the equation and type the ordered-palrs.<br> Y = 2^x
PSYCHO15rus [73]
What is the question
5 0
3 years ago
Other questions:
  • Identify the independent and dependent variables in the situation. The amount of electricity used for air conditioning in homes
    15·1 answer
  • 5
    15·1 answer
  • N/15 = 17/34 what does N equal
    13·1 answer
  • Line L passes through the points (0 - 3) and (6,9).
    9·1 answer
  • Which could be the area of the base of the triangular prism?
    7·1 answer
  • Some help with this pleaseee!
    5·1 answer
  • What is the volume of three cubes, each with a side length of fraction 1 over 3 foot? V = s3, where s is the side length.
    8·1 answer
  • Find the area of a trapezoid with a base 1 of 13 cm, base 2 of 9 cm, and height of 11 cm.
    9·1 answer
  • A telegraph pole is 70 m high. Its shadow is 100 m in length. Find the length of the tip of the shadow and the sun.
    7·1 answer
  • Even if the U.S. decides to remain neutral in an international conflict, after hostilities end the Peace Corps may become involv
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!