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3 years ago

5

Solve 13+x>11. Enter your answer as an equality

1 answer:

Wittaler [7]3 years ago

5 0

Answer:

x>-2

Step-by-step explanation:

13+x>11

Subtract 13 from each side

13-13+x>11-13

x>-2

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Answer:

Part 1) $x-2y=2$ ----> (2,0) and (0,-1)

Part 2) $-3x+3y=7$ ----> (-7/3,0) and (0,7/3)

Part 3) $7x-y=21$ ----> (3,0) and (0,-21)

Part 4) $3x-5y=-20$ ----> (-20/3,0) and (0,4)

Step-by-step explanation:

we know that

The y-intercept is the value of y when the value of x is equal to zero

The x-intercept is the value of x when the value of y is equal to zero

Part 1) we have

$x-2y=2$

1) <u><em>Find the x-intercept</em></u>

For y=0

$x-2(0)=2\\x=2$

the x-intercept is (2,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

$0-2y=2\\y=-1$

the y-intercept is (0,-1)

Part 2) we have

$-3x+3y=7$

1) <u><em>Find the x-intercept</em></u>

For y=0

$-3x+3(0)=7\\x=-\frac{7}{3}$

the x-intercept is (-7/3,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

$-3(0)+3y=7\\y=\frac{7}{3}$

the y-intercept is (0,7/3)

Part 3) we have

$7x-y=21$

1) <u><em>Find the x-intercept</em></u>

For y=0

$7x-(0)=21\\x=3$

the x-intercept is (3,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

$7(0)-y=21\\y=-21$

the y-intercept is (0,-21)

Part 4) we have

$3x-5y=-20$

1) <u><em>Find the x-intercept</em></u>

For y=0

$3x-5(0)=-20\\x=-\frac{20}{3}$

the x-intercept is (-20/3,0)

2) <u><em>Find the y-intercept</em></u>

For x=0

$3(0)-5y=-20\\y=4$

the y-intercept is (0,4)

8 0

3 years ago