F(x) = 3x^2+6x-2
= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5
So our function is in the form:
f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
Answer:
I don't understand what you want me to do
Step-by-step explanation:
Um i was thinking 5% or something like that
Answer:
it depend
Step-by-step explanation:
hopefully i help
Answer:
A the front of her check only
Step-by-step explanation:
When you receive a check the back doesn't have anything on the back that you write on hope this helps.
