Question

What is the equation of a line with a slope of ​3​ and a point (3, 1) on the line?

Answer 1

The answer is:
y = 3x - 8 

Find b by plugging in the point (x,y) which is (3,1).
1= 3(3)+b
1= 9 + b
-8 = b

Answer 2

Answer: The answer is $y=3x-8.$

Step-by-step explanation: We are given to find the equation of a straight line in slope-intercept form if the slope of the line is 3 and it passes through the point (3, 1).

We know that the slope-intercept form of a line is given by

$y=mx+c,$

Where 'm' is the slope and 'c' is the y-intercept of the line.

Here, we have

m = 3 and one point is (3, 1), so the equation of the line will be

$y-1=3(x-3)\\\\\Rightarrow y=3x-9+1\\\\\Rightarrow y=3x-8.$

Thus, the required equation is $y=3x-8.$