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Savatey [412]
3 years ago
12

PLEASE HELP NEED STEP BY STEP EXPLAINATION!!!then ƒ(2) =

Mathematics
2 answers:
andrezito [222]3 years ago
7 0
Swap x and y, f^-1 is and solve for y to get f^-1 the inverse of f. f(f^-1)=f^-1(f)=x is the identity as a check
f(2)=3*2+1=7 (2,7)
f^-1(7)=2 (7,2)
Effectus [21]3 years ago
3 0
I found out that f(2)=3*2+1=7 (2,7)
f^-1(7)=2 (7,3)f


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Make a tree diagram and find each probability.
Dafna11 [192]

Answer:  a) probability that the game will be canceled= 45%

b) probability there will be a light drizzle and the game will not be canceled=20%

Step-by-step explanation:

Since we have given that

Probability of heavy fog is given by

P(F)=0.70

Probability of a light drizzle is given by

P(D)=0.30

Probability of getting canceled a softball game due to light drizzle is given by

P(C\mid D)=0.80

Probability of getting canceled a softball game due to heavy fog is given by

P(C\mid F)=0.30

a. Find the probability that the game will be canceled.

Probability of getting the game be cancelled is given by

P(C)=P(F)\times P(C\mid F)+P(D)\times P(C\mid D)\\\\P(C)=0.70\times 0.30+0.30\times 0.80\\\\P(C)=0.45\\\\P(C)=45\%

b. Find the probability there will be a light drizzle and the game will not be canceled.

Probability that there will be a light drizzle and the game will not be canceled is given by

P(C'\mid D)=1-P(C\mid D)\\\\P(C'\mid D)=1-0.80\\\\P(C'\mid D)=0.20\\\\P(C'\mid D)=20\%

Hence, a) probability that the game will be canceled= 45%

b) probability there will be a light drizzle and the game will not be canceled=20%

8 0
3 years ago
What is the domain of g(x)?
yulyashka [42]
The domain of g(x) is A.All real numbers
3 0
4 years ago
-3+15mx=q <br><br> Solve for m
rjkz [21]

Answer:

m = q+3/15x

step-by-step explanations:

3 0
3 years ago
Mis himley picked 46 tomatoes from her garden on friday. On saturday she picked 17 tomatoes. How many tomatoes did she pick?
Leya [2.2K]
46 + 17 = 63. totally tomatoes she picked
4 0
3 years ago
Urn I contains three red chips and one white chip. Urn II contains two red chips and two white chips. One chip is drawn from eac
Lelechka [254]

Answer:

0.7

Step-by-step explanation:

The Probability of Chips in Urn 1

P(R) = 3/4

P(W) = 1/4

The Probability of Chips in Urn 2

P(R) = 1/2

P(W) = 1/2

The problem can be solved using probability tree method. The probability tree of the given question is attached with the answer.

The Probability tree shows the exchange of chips firstly and then the final probability of Red Chips and White Chips in Urn 1.

To find the final answer we can sum up the probabilities of the branches which are ticked in the diagram.

Probability of Branch 1 (ticked in diagram)

3/4 x 3/5 x 3/4 = 0.3375

Probability of Branch 2 (ticked in diagram)

3/4 x 2/5 x 2/4 = 0.15

Probability of Branch 3 (ticked in diagram)

1/4 x 2/5 x 1 = 0.1

Probability of Branch 4 (ticked in diagram)

1/4 x 3/5 x 3/4 = 0.1125

Final Probability = 0.3375 + 0.15 + 0.1 + 0.1125

= 0.7 Answer

7 0
3 years ago
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