Answer: 1 and 3
Step-by-step explanation:
I had the same question on my test the other day hope this helped.
to find the area of the figure, you first need to find the area of the separate figures: a triangle and a square.
first, find the area of the triangle:
multiply 13 and 5 to get 65.
divide 65 by 2.
32.5.
then, find the area of the rectangle:
multiply 5 and 14 to get 70.
add those answers up, and you get:
102.5
Answer:
Given
Number of stacks = 2
Stack 1 = 6 cups; h1 = 15cm
Stack 2 = 12 cups; h2 = 23cm
Let's first find the average:
With an average of 4/3, to obtain the number of cups needed to obtain a height of 50m, we have:
50 / (4/3)
= 50 * 3/4
= 150/4
= 37.5
From the answer, we can see that the number of cups is not really proportional to the height of the stack, because the average of stack one and stack 2 are different.
Step-by-step explanation:
Answer:
i)D:
ii)R: 
iii) Y-int:(0,-1)
Step-by-step explanation:
i) The given absolute value function is;
.
The absolute value function is defined for all real values of x.
The domain is all real numbers.
ii) The range is all y-values that will make x defined.
The given function,
.
has vertex at, (-2,-3) and opens upwards.
This implies that, the minimum y-value is -3.
The range is 
iii) To find the y-intercept substitute x=0 in to the function.
.
.
.
.
The y-intercept is (0,-1)
See attachment for graph.
Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
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Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
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Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
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At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21