Question

The diagram shows a cuboid

Answer 1

Answer:

AE = 21.471cm long

(Rounded to 3 sig figs would be 21.5cm)

Step-by-step explanation:

Use the pythagorean theorem to find the length of AH

10^2 + AH^2 = 25^2

AH^2= (625 - 100)

AH = Square root of (525)

AH = 22.913

Plug in this value for AH to solve for AE using the pythagorean theorem

HE^2 + AE^2 = AH^2

8^2 + AE^2 = 22.913^2

AE^2 = 525 - 64

AE = Square root of (461)

AE = 21.4709

Hope this helps!

Answer 2

Answer:

AE=21.47

Step-by-step explanation:

trg ABD I apply the Pitagorean Theoreme

BD^2=10^2+8^2=100+64=164

trg  HDB I apply the Pitagorean Theoreme

DH^2+BD^2=BH^2

DH^2+164=25^2

DH^2+164=625

DH^2=625-164=461

DH=V461=21.47

AE=DH=21.47