Answer: Like the angles BAC (56°) and BDC has the same arc BC in the circumference, these angles must be congruent, then angle BDC must be equal to 56°.
You just need to solve for when
:
![\dfrac{\cos8t-9\sin8t}4=0\implies\cos8t-9\sin8t=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ccos8t-9%5Csin8t%7D4%3D0%5Cimplies%5Ccos8t-9%5Csin8t%3D0)
![\implies\cos8t=9\sin8t](https://tex.z-dn.net/?f=%5Cimplies%5Ccos8t%3D9%5Csin8t)
![\implies\dfrac19=\dfrac{\sin8t}{\cos8t}=\tan8t](https://tex.z-dn.net/?f=%5Cimplies%5Cdfrac19%3D%5Cdfrac%7B%5Csin8t%7D%7B%5Ccos8t%7D%3D%5Ctan8t)
![\implies8t=\tan^{-1}\dfrac19+n\pi](https://tex.z-dn.net/?f=%5Cimplies8t%3D%5Ctan%5E%7B-1%7D%5Cdfrac19%2Bn%5Cpi)
![\implies t=\dfrac18\tan^{-1}\dfrac19+\dfrac{n\pi}8](https://tex.z-dn.net/?f=%5Cimplies%20t%3D%5Cdfrac18%5Ctan%5E%7B-1%7D%5Cdfrac19%2B%5Cdfrac%7Bn%5Cpi%7D8)
where
is any integer. We only care about when
, which happens for
.
![t=\dfrac18\tan^{-1}\dfrac19\approx0.01](https://tex.z-dn.net/?f=t%3D%5Cdfrac18%5Ctan%5E%7B-1%7D%5Cdfrac19%5Capprox0.01)
![t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi8\approx0.41](https://tex.z-dn.net/?f=t%3D%5Cdfrac18%5Ctan%5E%7B-1%7D%5Cdfrac19%2B%5Cdfrac%5Cpi8%5Capprox0.41)
![t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi4\approx0.80](https://tex.z-dn.net/?f=t%3D%5Cdfrac18%5Ctan%5E%7B-1%7D%5Cdfrac19%2B%5Cdfrac%5Cpi4%5Capprox0.80)
5.37796e13 please don't waste our time.
Answer:When a point is reflected it must be reflected over a line
The transformation from K to K' is a reflection over the y-axis
The transformation from I to I' is a reflection over the line y= -x
From the complete question, the given parameters are:
c
(a) From K to K'
We have:
Notice that, only the x-coordinate of point K is negated to form point K'
This means that: the transformation from K to K' is:
Step-by-step explanation: Answer: y-axis, y=-x
Combining like terms on both sides is 2x+6=x+13