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Olegator [25]
2 years ago
6

A population of 200 animals has a growth rate of 1.03% each year. at this growth rate, the function f(x)=200(1.03)^x gives the p

opulation in x years. in how many years will the population first reach 300? answer
Mathematics
1 answer:
Y_Kistochka [10]2 years ago
6 0
For this case, the first thing we should do is use the following equation:
 f (x) = 200 (1.03) ^ x
 We substitute f (x) = 300:
 300 = 200 (1.03) ^ x
 We clear the value of x:
 log1.03 (300/200) = log1.03 ((1.03) ^ x)
 x = log1.03 (300/200)
 x = 13.72
 Answer: 
 the population will first reach 300 in about 13.72 years.
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The short side is _15___ft and the long side is ___30___ ft.

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As fence is built in a rectangular area, so we can consider

Let

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y be width of the rectangle

Given area of rectangle is = 450 ft²

Formula for area of rectangle = Length x width  

     450 ft² =  xy  

Solve for y

y = 450/x            

now according to given condition  

three sides of the fence costs $5 per foot and for the fourth side costs$15 per foot.

We have two condition either the fourth side be x or y

So condition 1:  Three sides =(x,y,x)       4-th side = y.

So  we can write as 5x,5y,5x  and  15 y  

Cost C = 5x +5y+5x+15y

         = 10x+ 5y+15y

         = 5(2x+y) +15y----------------equation 1

           = 10x +20y

Adding value of y 450/x

        = 10x + 20(450/x)

  = 10x + 9000/x

For minimum cost, we can consider the cost to be 0

 0 = 10x + 9000/x

Dividing and multiplying by -x/x

0 = -10 +9000/x²

10 = 9000/x²

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x = 30

so y = 450/x = 450/30= 15 ft  

so adding the values of x and y in equation 1 we will have

cost C= 5(2x+y) +15y----------------equation 1

cost is          = 5(2(30)+15) +15(15)

                      =  $600 is the cost  

X= 30 y =15

So condition 2:  Three sides =(y,x,y)       4-th side = x.

So  we can write as 5y,5x,5y  and  15 x

Cost C = 5y +5x+5y+15x

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For minimum cost, we can consider the cost to be 0

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Dividing and multiplying by -x/x

0 = -20 +4500/x²

20 = 4500/x²

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x = 15

so y = 450/x = 450/15= 30 ft  

so adding the values of x and y in equation 2 we will have

cost C= = 5(x+2y) +15x----------------equation 2

cost is          = 5(15+2(30) +15(15)

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y= 30 x=15

so from both conditions satisfy the cost and the two sides are known as length and width

so dimension will be 15 ft by 30 ft  

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