Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
Answer:
b = (a/16) - 4
Step-by-step explanation:
a = 16(b + 4)
a = 16b + 64
16b + 64 = a
16b = a - 64
16b/16 = (a/16) - 64/16
b = (a/16) - 4
Answer:
Each angle is 67 degrees
Step-by-step explanation:
Bisected angles are divided in half
134/2 =67
Each angle is 67 degrees
In 
,
$a$ is the real part
$ib$ is the imaginary part.
Comparing, we get:
Real part: $91$
Imaginary part: $-27i$
