18 points

You make $6,600 annual deposits into a retirement account that pays an APR of 11.1 percent compounded monthly How large will you

elena-s [515]

The account balance would be $9,293.12 or 11 cents.

7 0

2 years ago

Write the equation of the line that passes through the points (2,−8) and (1,7). Put your answer in fully reduced point-slope for

ValentinkaMS [17]

Point-slope form of equation is: $y - 7 = -15(x-1)$

Step-by-step explanation:

Given points are:

(2,-8) and (1,7)

First of all we have to calculate the slope of the line

so,

$m=\frac{y_2-y_1}{x_2-x_1}\\= \frac{7-(-8)}{1-2}\\=\frac{7+8}{-1}\\=\frac{15}{-1}\\= -15$

Point-slope form is given by:

$y-y_1 = m(x-x_1)$

Putting the value of slope

$y-y_1 = -15(x-x_1)$

We can put any one of two given points in the equation to find the final form of point-slope form

So

Putting (1,7) in the equation

$y - 7 = -15(x-1)$

Hence, point-slope form of equation is: $y - 7 = -15(x-1)$

Reducing and simplifying

$y - 7 = -15(x-1)\\y-7 = -15x+15\\y-7+7 =-15x+15-7\\y = -15x+8\\15x+y = 8$

Keywords: Point-slope form, equation of line

Learn more about equation of line at:

#LearnwithBrainly

8 0

2 years ago

PLZZ HELPP ILL GIVE BRAINLIST

VashaNatasha [74]

Answer:

multiply both sides by 3

7 0

2 years ago

2. What is the value of x? Show your work.

trapecia [35]

The answer will be 7.....value of x is 7 i believe

4 0

3 years ago

Read 2 more answers

In a class of 19 students, 3 are math majors. A group of four students is chosen at random. (Round your answers to four decimal

KatRina [158]

Answer:

(a) The probability is 0.4696

(b) The probability is 0.5304

(c) The probability is 0.0929

Step-by-step explanation:

The total number of ways in which we can select k elements from a group n elements is calculate as:

$nCx=\frac{n!}{x!(n-x)!}$

So, the number of ways in which we can select four students from a group of 19 students is:

$19C4=\frac{19!}{4!(19-4)!}=3,876$

On the other hand, the number of ways in which we can select four students with no math majors is:

$(16C4)*(3C0)=(\frac{16!}{4!(16-4)!})*(\frac{3!}{0!(3-0)!})=1820$

Because, we are going to select 4 students form the 16 students that aren't math majors and select 0 students from the 3 students that are majors.

At the same way, the number of ways in which we can select four students with one, two and three math majors are 1680, 360 and 16 respectively, and they are calculated as:

$(16C3)*(3C1)=(\frac{16!}{3!(16-3)!})*(\frac{3!}{1!(3-1)!})=1680$

$(16C2)*(3C2)=(\frac{16!}{2!(16-2)!})*(\frac{3!}{2!(3-1)!})=360$

$(16C1)*(3C3)=(\frac{16!}{1!(16-1)!})*(\frac{3!}{3!(3-3)!})=16$

Then, the probability that the group has no math majors is:

$P=\frac{1820}{3876} =0.4696$

The probability that the group has at least one math major is:

$P=\frac{1680+360+16}{3876} =0.5304$

The probability that the group has exactly two math majors is:

$P=\frac{360}{3876} =0.0929$

6 0

2 years ago