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3 years ago

Which statement best explains if the graph correctly represents the proportional relationship y = −2x?

Mathematics

2 answers:

Anvisha [2.4K]3 years ago

8 0

<span>d. It does, the points shown on the line would be part of y = −2x.
is the answer let me know if this helped</span>

kvv77 [185]3 years ago

6 0

Answer:

So, it does, the points shown on the line would be part of y = −2x.

Step-by-step explanation:

1)The linear function $y=-2x$ is a decreasing one therefore it is graphed from 2nd Quadrant to 4th Quadrant. In addition to this, since is linear parameter <em>b</em> is equal to zero, the line crosses its origin. Finally, its slope is equal to -2.

2)We have (-1,2) and (2,4), pointed out. Linear functions with b=0 are proportional ones. Proportional functions have its slope calculated by:

$k=\frac{y}{x}=\frac{2}{-1}=\frac{4}{-2}\Rightarrow k=-2$

So, it does, the points shown on the line would be part of y = −2x.

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Single Factor ANOVA is a method we use when we want to compare a quantitative variable among more than two categories.

Goryan [66]

Answer:

The given statement is "True".

Step-by-step explanation:

A statistical analytical technique that divides the perceived aggregate unpredictability present throughout an information source even further into 2 components.

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If relevant information yet another category independent variable, as well as another quantifiable variable of interest, has been obtained, are using a single-way ANOVA.

Thus the above is the true answer.

3 0

3 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

The degree of 4 – x2

Elina [12.6K]

Answer:

Step-by-step explanation:

If the given is x^2 then the degree is 2.

Degree: 4 - x^2 = 2.

It is what is on the x to the highest power. If the question was

x^3 - 3x^2 + 2x + 4

The the degree would be 3

6 0

2 years ago

Please include how to solve this!! Thanks you!

arlik [135]

Circle=27, triangle=18, and square=26

Start with the second question. If you divide 36 by 2, you get 18 which is the value for the triangle. Now since you know the value of the triange you subtract it from 45. (45-18=27) 27 is the value of the circle. Lastly, subtract 27 from 53 to get the value of the square (53-27=26). Hope this helps!

5 0

3 years ago

What is 14/25 as a percent

coldgirl [10]

You simply divide, since it's a fraction. If you divide 14 b7 25, you get an answer of 0.56. :)

8 0

3 years ago

Read 2 more answers