Answer:
So, it does, the points shown on the line would be part of y = −2x.
Step-by-step explanation:
1)The linear function
is a decreasing one therefore it is graphed from 2nd Quadrant to 4th Quadrant. In addition to this, since is linear parameter <em>b</em> is equal to zero, the line crosses its origin. Finally, its slope is equal to -2.
2)We have (-1,2) and (2,4), pointed out. Linear functions with b=0 are proportional ones. Proportional functions have its slope calculated by:
![k=\frac{y}{x}=\frac{2}{-1}=\frac{4}{-2}\Rightarrow k=-2](https://tex.z-dn.net/?f=k%3D%5Cfrac%7By%7D%7Bx%7D%3D%5Cfrac%7B2%7D%7B-1%7D%3D%5Cfrac%7B4%7D%7B-2%7D%5CRightarrow%20k%3D-2)
So, it does, the points shown on the line would be part of y = −2x.