Suppose

The mean annual tuition and fees for a sample of 15 private colleges was with a standard deviation of . A dotplot shows that it

Fudgin [204]

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

The mean annual tuition and fees for a sample of 15 private colleges was $35,500 with a standard deviation of $6500. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $32,500. State the null and alternate hypotheses. A) H0: 4 = 32,500, H:4=35,500 C) H: 4 = 35,500, H7:35,500 B) H: 4 = 32,500, H : 4 # 32,500 D) H0:41 # 32,500, H : 4 = 32,500

Solution

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 32500

For the alternative hypothesis,

Ha: µ ≠ 32500

This is a two tailed test.

Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.

Since n = 15,

Degrees of freedom, df = n - 1 = 15 - 1 = 14

t = (x - µ)/(s/√n)

Where

x = sample mean = 35500

µ = population mean = 32500

s = samples standard deviation = 6500

t = (35500 - 32500)/(6500/√15) = 1.79

We would determine the p value using the t test calculator. It becomes

p = 0.095

Assuming alpha = 0.05

Since alpha, 0.05 < than the p value, 0.095, then we would fail to reject the null hypothesis.

7 0

3 years ago

Penelope made note of all the bicycles and cars she could see parked or locked on acertain city block. All the cars had exactly

lesantik [10]

Given:

The number of cycles is, n (s) = 7.

The number of wheels in the cycle is, n (sw) = 2.

The number of cars is, n (c) = 15.

The number of wheels in the car is, n (cw) = 4.

The obective is to find the total number of wheels.

The total number of wheels is,

$\begin{gathered} T=n(sw)\cdot n(s)+n(cw)\cdot n(c) \\ =2\cdot7+4\cdot15 \\ =14+60 \\ =74\text{ whe}els \end{gathered}$

Hence, there are 74 wheels in the block.

If there are x bicycles and y cars, the equatioin will be,

$\begin{gathered} T=n(sw)\cdot x+n(ce)\cdot15 \\ T=2x+4x \end{gathered}$

Hence, the number of wheels for x bicycles and y cars is 2x+4x.

6 0

1 year ago

8x + 34. What does X equal

rosijanka [135]

Answer: $x=-4.25$

Step-by-step explanation:

First you put it in to y= mx+b form.

$0=8x+34$

Then you subtract 34 from both sides

$-34=8x$

Then you divide 8 from both sides

Leaving you with

$x=-4.25$

4 0

3 years ago

PLEASE HELP I NEED THIS ASAP

vivado [14]

Answer:

you should've paid attention in class :/

Step-by-step explanation:

8 0

2 years ago

Use the algebraic expressions for the length and width of Marlene's living room found in the

krok68 [10]

Answer:

The area of Marlien's living room is 420 square ft

Step-by-step explanation:

Before calculating the real dimensions of Marlien's living room, we must find the value of x.

Given the total shape of the house is a rectangle, then both widths must be equal and both lengths must be equal.

The widths are already written width identical expressions x-2+x, but the lengths are given as different functions of x. Equating both expressions, we have:

$2x-10+x-2+\frac{1}{2}x-4+x-2=2x+2+\frac{1}{2}x-4+x-2$

Simplifying:

-10 + x - 2 = 2

x = 10 + 2 + 2

x = 14

Since x=14 feet, the dimensions of Marlien's living room are

width=x=14 feet

length=2x+2=30 feet

Thus the area is:

A = 14*30 = 420 square ft

The area of Marlien's living room is 420 square ft

8 0

3 years ago