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N76 [4]
3 years ago
12

What are the x-intercepts of the function f(x) = –2x2 – 3x + 20? (–4, 0) and and (4, 0) (–5, 0) and (2, 0) (–2, 0) and (5, 0)

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

Step-by-step explanation:

If you would like to find the x-intercepts of the function f(x) = - 2 * x^2 - 3 * x + 20, you can calculate this using the following steps:

f(x) = - 2 * x^2 - 3 * x + 20

f(x) = - (2x - 5) * (x + 4)

1. x = - 4

2. x = 5/2

(x, y) = (-4, 0)

The correct result would be (-4, 0).

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If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}

Therefore, the correct option is (3).

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3 years ago
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It takes chris 30 mininutes to walk to work it takes him 1/3 of the time to drivewhat is the latesest time he can drive to work
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