Answer:
Width of Rectangle is 6 cm.
Length of Rectangle is 38 cm
Step-by-step explanation:
Given:
Area of Rectangle = ![228cm^2](https://tex.z-dn.net/?f=228cm%5E2)
Perimeter of rectangle = 88 cm
Let width be x cm
according to given data Length =![5x+8](https://tex.z-dn.net/?f=5x%2B8)
Solution:
Formula for Perimeter of Rectangle = ![2(length+width)](https://tex.z-dn.net/?f=2%28length%2Bwidth%29)
Substituting the above given data in the stated formula we get.
![2(8+5x+x)=88](https://tex.z-dn.net/?f=2%288%2B5x%2Bx%29%3D88)
Dividing both sides by 2 we get
![\frac{2(8+6x)}{2}=\frac{88}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2%288%2B6x%29%7D%7B2%7D%3D%5Cfrac%7B88%7D%7B2%7D)
![8+6x=44](https://tex.z-dn.net/?f=8%2B6x%3D44)
Subtracting both side by 8 we get.
![8+6x-8=44-8](https://tex.z-dn.net/?f=8%2B6x-8%3D44-8)
![6x=36](https://tex.z-dn.net/?f=6x%3D36)
Dividing both side by 6 we get.
![\frac{6x}{6}=\frac{36}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B6x%7D%7B6%7D%3D%5Cfrac%7B36%7D%7B6%7D)
![\therefore x=6](https://tex.z-dn.net/?f=%5Ctherefore%20x%3D6)
Width of the rectangle is 6 cm
Now length= ![8+5x=8 + 5\times6=8+30=38](https://tex.z-dn.net/?f=8%2B5x%3D8%20%2B%205%5Ctimes6%3D8%2B30%3D38)
Length of the rectangle is 38 cm
Answer:
yes u can but i dont know how to show u becuase i cant move them round
Step-by-step explanation:
Answer:
8t(t - 5)^2
Step-by-step explanation:
I would immediately rearrange these terms in descending order by powers of t:
8t^3 - 80t^2 + 200t
Then I'd factor out 8t:
8t(t^2 - 10 t + 25).
Finally, I'd factor the quadratic t^2 - 10 t + 25:
(t - 5)^2
and so 200t+8t^3-80t^2 in factored form is 8t(t - 5)^2.
Answer:
B
Step-by-step explanation:
Answer:
((7*2)*(8p))
Step-by-step explanation:
The product of 7 and 2 basically means you multiply them. The product of 7 and 2 is 14 and the product of 8p cannot be known because p is undefined so keep it as 8p. the product of 14 and 8p is 112p but the answer I stated above is the unsimplified version.