The formula we use for continuous compounding is
where P is the initial amount invested, r is the rate as a decimal, and t is time in years. Our P = 1300, our r = .042, and our t = 5.75 (9 months is 3/4 of a year, and 3/4 in a decimal is .75). Putting all that into our formula we have
. We have to multiply those 2 powers together and then raise euler's number to it, then multiply by 1300. Doing all of that, we get the amount at the end to be $1,655.10
Answer:
Area of the trapezium ABDE = 30 cm²
Step-by-step explanation:
Area of a trapezium = 
Here, 
and 
are the parallel sides of the trapezium
h = Distance between the parallel sides
From the picture attached,
ΔCAE and ΔCBD are the similar triangles.
So by the property of similarity their sides will be proportional.
CE = 
CE = 12 cm
Therefore, DE = CE - CD
DE = 12 - 8 = 4 cm
Now area of trapezium ABDE = 
= 
= 30 cm²
Therefore, area of the trapezium ABDE = 30 cm²
Answer:
Segunda etapa= 123.75 metros
Step-by-step explanation:
Altura total= 225 metros
<u>En la primera estapa subió el 20% (un quinto):</u>
Primera etapa= 225*0.2= 45 metros
<u>En la tercera etapa subió 25% (un cuarto):</u>
Tercera etapa= 225*0.250 56.25 metros
Ahora debemos determinar cuánto subió en la segunda etapa:
Segunda etapa= altura total - total subido
Segunda etapa= 225 - (45 + 56.25)
Segunda etapa= 123.75 metros
In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.
In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.
In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...
9/17 = 18/34
15/34
6/17 = 12/34
9/34
Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.
This would match the definition of an arithmetic sequence and NOT a geometric sequence.
Note that f(1) = 6(1)+2 = 8. Next, evaluate g(x) at x=8: g(f(1)) = g(8) = 2(8) + 4/5, or 16 4/5.
