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vivado [14]
2 years ago
15

What is the solution for the proportion below 8/9 = m / 72?

Mathematics
1 answer:
Wittaler [7]2 years ago
8 0
The I believe the answer is m= 64
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Justify each step in solving the equation 5(y+3)-11=-y-6 by writing a reason for each statement.
liubo4ka [24]

Explanation:

5(y+3)-11=-y-6 Given

5(y+3)=-y+5 . . . . addition property of equality (11 is added)

5y+15=y+5 . . . . . distributive property (5 is distributed)

5y=-y-10 . . . . . . . addition property of equality (-15 is added)

6y=-10 . . . . . . . . . addition property of equality (y is added)

y=-5/3 Division Property of Equality/Reduce

6 0
3 years ago
You are assigned 32 math exercises for homework. You complete 87.5% of these before dinner. How many do you have left to do afte
Hunter-Best [27]
You would have 4 left after dinner: (.875)(32)=28 so you have 28 completed before dinner and would have 4 left to do.
7 0
3 years ago
WILL GIVE BRAINLIEST!!!!!!
Dahasolnce [82]
<h2>Greetings!</h2>

Answer:

x = 67.5

Step-by-step explanation:

Because AB and NP lines are parrallel, we can find out the scale factor by dividing size MA by MN.

This works because you find out what the MA size has to be multiplied to to get to MN, which will also work in reverse to find angle MB from MP.

71.5 - 22 = MA = 49.5

71.5 ÷ 49.5 = \frac{13}{9}

So to get to line MP length, line MB had to be multiplied by \frac{13}{9} to get 97.5

The reverse of this is dividing 97.5 by \frac{13}{9}:

97.5 ÷ \frac{9}{13} = 67.5

So x = 67.5


<h2>Hope this helps!</h2>
4 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
3 years ago
Read 2 more answers
Can you guys help me wit number 7 please nn thanks
Vaselesa [24]

Answer:

10 to the power 3

Step-by-step explanation:

10 to the power 6 divided by 10 to the power 3 is 10 to the power 3.

3 0
2 years ago
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