Question

Factor completely. 12x4+18x3+45x2 Enter your answer in the box.

Answer 1

QUESTION 1

The given expression is

$12x^4+18x^3+45x^2$

The greatest common factor is $3x^2$.

We factor to obtain;

$3x^2(4x^2+6x+15)$

QUESTION 2

The given quadratic equation is

$x^2+6x-72=0$

We split the middle term to obtain

$x^2+12x-6x-72=0$

Factor by grouping;

$x(x+12)-6(x+12)=0$

$(x+12)(x-6)=0$

Use zero product property;

$(x+12)=0\:\:or\:\:(x-6)=0$

$x=-12\:\:or\:\:x=6$

QUESTION 3

The given system of equation is

$3x+4y=-8$

$7x-3y=6$

If we multiply $3x+4y=-8$ by 3, we obtain;

$9x+12y=-24$

If we multiply $7x-3y=6$ by 4 we obtain;

$28x-12y=24$

Adding the last two equations will give us;

$37x=0$

The y-variable is eliminated.

Answer:Multiply 3x+4y=−8

by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.