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boyakko [2]
4 years ago
7

What is the mean for this list of numbers? 17, 19, 21, 23

Mathematics
2 answers:
Svetlanka [38]4 years ago
7 0

Answer:

The mean is 20

Step-by-step explanation:

17+19+21+23=80

80 div 4 = 20

pychu [463]4 years ago
5 0

Answer:

20.

Step-by-step explanation:

The mean = (sum of the numbers)  / 4   as there are  a total 4 numbers in the list.

Mean = (17+19+21+23) / 4

= 80 / 4

= 20.

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hoa [83]

Answer:

7,500,000

Step-by-step explanation:

Basically times 2,500,000 by 3

5 0
3 years ago
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What is the solution to this equation? 3 square root (1/8-x)=-1/2<br> NEED ANSWER ASAP please
timofeeve [1]

Answer:

x is 10

Step-by-step explanation:

8 0
3 years ago
In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two
bogdanovich [222]

Answer:

The probability that​ his/her household has four or more cell phones in use is 0.122 or 12.2%.

Step-by-step explanation:

<u>The complete question is</u>: In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two respondents were from the same​ household.) Among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

We are given that among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more.

A survey respondent is selected at random.

As we know that the probability of any event is calculated as;

                Probability = \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

Here, we have to find the probability that​ his/her household has four or more cell phones in use;

Number of respondent having four or more cell phones in use = 140

Total number of respondents asked = 215 + 280 + 362 + 149 + 140 = 1146

<u>So, the required probability</u> = \frac{140}{1146}

                                              = 0.122 or 12.2%

No, it is not unlikely for a household to have four or more cell phones in​ use because the probability is not less than or equal to 0.05 but in actual it is greater than 0.05.

6 0
3 years ago
Question 1 help! Please!
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Answer: D

Step-by-step explanation:

6 0
3 years ago
If my paycheck was $1,417 and they take out 5% of that how much are they taking out​
docker41 [41]

Answer:

70.85

Step-by-step explanation:

have a great time bro

5/100*1417

6 0
3 years ago
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