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vichka [17]
3 years ago
7

Help? Solve the system of equations. y = 3x y = x2 + 3x – 16 solutions: ( );( )

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

(- 4, - 12 ) , (4, 12 )

Step-by-step explanation:

Given the 2 equations

y = 3x → (1)

y = x² + 3x - 16 → (2)

Substitute y = x² + 3x - 16 into (1)

x² + 3x - 16 = 3x ( subtract 3x from both sides )

x² - 16 = 0 ( add 16 to both sides )

x² = 16 ( take the square root of both sides )

x = ± \sqrt{16} = ± 4

Substitute these values into (1) for corresponding values of y

x = - 4 : y = 3 × - 4 = - 12 ⇒ (- 4, - 12 )

x = 4 : y = 3 × 4 = 12 ⇒ (4, 12 )

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5 0
3 years ago
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4 0
2 years ago
If 7x - 4y = 23 and x + y = 8, what is the value of x?
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x=5

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------------------------

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