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Alexeev081 [22]
2 years ago
11

50 5x + 15 Value of x

Mathematics
1 answer:
GenaCL600 [577]2 years ago
5 0

Answer:

4 love u davy

Step-by-step explanation:

You might be interested in
A toy rocket is shot vertically into the air from a launching pad 9 feet above the ground with an initial velocity of 168 feet p
hammer [34]
Y(initial) = 9
V(initial) = 168
V(final) = 0
g(accel-grav) = 32 (in feet per second
squared)
Use the following equation:
V(final) = V(initial) + a(t)
Since this object is moving straight up and
down, a = -32
Enter the knowns into the equation
0 = 168 - 32t
32t = 168
t = 168/9.8
t = 5.25

Now that you know the time it takes to
reach it's maximum, use the general
kinematics equation to solve for final
distance:

y(final) = y(initial) + V(initial)(t) + (1/2)a
(t²)

y(final) = 9 + 168(5.25) + (1/2)(-32)
(5.25²)

= 9 + 882 - 441

= 450 feet
5 0
3 years ago
Read 2 more answers
Please help plz and explain
Liono4ka [1.6K]

Answer:

letter d or b

srry if wrong hope thiss helped

8 0
2 years ago
If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph
Lelechka [254]
The answer is 12 because the linear equation is mx+b,where m is the slope and b is the y-intercept.
7 0
3 years ago
A croissant shop produces two products: bear claws (B) and almond filled croissants (C). Each bear claw requires 6 oz of flour,
Kruka [31]

Answer:

letter A: B = 400; C = 1000; Max Z = $380

Step-by-step explanation:

bear claws (B) need 6 oz of flour (f), 1 oz of yeast (y), 2 ts of paste (p)

croissants (C) need 3 oz of flour (f), 1 oz of yeast (y), 4 ts of paste (p)

putting that information in equations, we have:

B = 6f + y + 2p

C = 3f + y + 4p

The total number of resources (R) are:

R = 6600f + 1400y + 4800p

Let's call M our total profit, "k1" the number of B produced and "k2" the number of C produced.

So, we can state that:

M = k1*0.2 + k2*0.3

The number of resources R2 will demand is calculated like this:

R2 = k1*B + k2*C = (6k1+3k2)f + (k1+k2)y + (2k1+4k2)p

using R2 and R, we can make some inequations:

6k1+3k2 <= 6600 -> 2k1+k2 <= 2200

k1+k2 <= 1400

2k1+4k2 <= 4800 -> k1+2k2 <= 2400

if we try to maximize k2 (as it worths more), we will have k1 = 0 and k2 = 1200 (limited by p), but looking at the resources R, we will still have resources to use (f and y). Looking at B and C expressions, we see that removing one C gives enough 'p' to make 2 B, which is a good trade (as 2B worths 0.4 cents, and 1C worths 0.3 cents). we have 200 'y' remaining, so doing this 200 times give us k1 = 400 and k2 = 1000, and the only resource remaining will be some of 'f'.

calculating the profit M, we have:

M = 400*0.2 + 1000*0.3 = 380$

the right answer is letter A.

3 0
3 years ago
Help me please please
ratelena [41]
When dividing same numbers with different exponents (they’re both 10 so this works different than if they were different numbers) you subtract the top exponent by the bottom exponent. So 15-4=11 ultimately making the solution 10^11. Hope this helps :)
4 0
2 years ago
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