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Tpy6a [65]
3 years ago
12

What is the slope of a line parallel to the line x = 5?

Mathematics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

Undefined

Step-by-step explanation:

The slope of a line parallel to the line x = 5 is undefined because the line would be a straight vertical line. Vertical lines don't have a slope because it is impossible to measure rise/run. Hope this helps!

You might be interested in
Sewing patterns recommended buying extra fabric in case of mistakes. Darlene bought 7 yards of fabric, plus 20% extra fabric. Ch
Debora [2.8K]

Answer:

Darlene bought more fabric

Darlene bought 3.4 yards more

Step-by-step explanation:

Darlene = 7 yards + 20% extra

= 7 yards + (20% of 7 yards)

= 7 + (20% × 7)

= 7 + (0.2 × 7)

= 7 + 1.4

= 8.4 yards

Chris = 4 yards + 25% of 4 yards

= 4 yards + (25% of 4 yards)

= 4 + (25% × 4)

= 4 + (0.25 × 4)

= 4 + 1

= 5 yards

Darlene bought more fabric

How much more?

Darlene - Chris

= 8.4 yards - 5 yards

= 3.4 yards

Darlene bought 3.4 yards more

6 0
3 years ago
What’s the slope and equation
Pie
Y=-10x-100

Rise over run
5 0
3 years ago
Read 2 more answers
99.999 rounded to the nearest tenth would be?
ale4655 [162]

Answer:

Look at the place after the tenths, it is more than 5.

99.999

So add +1 to the tenths place.

Rounded to the nearest tenth would be:

<h2>100.0</h2>
4 0
4 years ago
Read 2 more answers
I need answer ASAP plz!!!
ANTONII [103]
It’s B I hope this helps :)
6 0
3 years ago
The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
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