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3 years ago

Please please answer this correctly

Mathematics

2 answers:

Katarina [22]3 years ago

8 0

876080119... ;) hope this helps Feni

Nutka1998 [239]3 years ago

5 0

Answer:

876,080,119

Step-by-step explanation:

Well first you add the big numbers first 80,000+70,000,000+6,000,000+800,000,000

which would equal 876,080,000 then add the numbers that seem small which was 100+10+9 you actually wouldn't have to use a calculator.

Hope this helped, have a good rest of your day. -bbygurl1002♡

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The point-slope form:

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2 years ago

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3 years ago

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Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

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..............x/sqrt(64-x^2)

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A. ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)

B . cos (arsin (x/8)) ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and $\sqrt{8^{2} - x^{2} }$ or $\sqrt{64 - x^{2} }$

thus tan(arcsin(x/8)) = $\frac{x}{\sqrt{64 - x^{2} }}$ =

Therefore ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)

Here we have cos = adjacent/hypotenuse where adjacent side is $\sqrt{64 - x^{2} }$ and hypothenuse = 8 we have $\sqrt{64 - x^{2} }$ /8

B . cos (arsin (x/8)) ....sqrt(64-x^2)/8

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