After putting the value of y from the second equation to the first equation, the resultant equation is
.
GIven:
The equations are:

It is required to put the value of y from second equation to the first equation.
<h3>How to solve equations?</h3>
The value of y from the second equation is,

Now, put this value of y in the first equation as,

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is
.
For more details about equations, refer to the link:
brainly.com/question/2263981
Answer:
78
Step-by-step explanation:
Given that:
First day (a) = 1
1 more pebble every subsequent day than the previous day
Tn = a + (n - 1)d
d = common difference ; difference between pebbles in two successive days = 1
n = nth day
At the end of the 12th day;
Tn = a + (n - 1)d
T(12) = 1 + (12 - 1) 1
T(12) = 1 + 11
T(12) = 12
Appling the sun if arithmetic progression formula : Sum of AP:
n/2 (a + Tn)
n = number of terms
12/2 (1 + 12)
6(13)
= 78
(6x6)x(6x6x6)=
(6x6x6x6x6)
((3x3x3)x(3x3x3)x(3x3x3)x(3x3x3))
try it on the calculator.
Answer:
5/2
Step-by-step explanation: