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Rasek [7]
3 years ago
11

If the area of a rectangle is x^2-9 and one dimension is x-3. what would be the other dimension?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

Step-by-step explanation:

x2-9 = 0

Area of one dimension = x-3= 0

So, x2= 9

Square root on both sides;

x= +3 and -3

x-3 is one side

x+3 is the other dimension

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Answer:

The required formula is:

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Step-by-step explanation:

The total number of squares of the the first term = 4

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If the initial term of an arithmetic progression is {\displaystyle a_{1}} and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by:

                         {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Therefore, the required formula is:

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