Answer:
The answer has many ongoing 3's so just shorten it to
8.3 or 8.33
From SOH CAH TOA,
.. cos(22°) = x/11 . . . . . fill in given values for C = A/H
.. 11*cos(22°) = x . . . . . multiply by 11
.. 11*0.927184 = x . . . .use a calculator to find cos(22°)
.. 10.1990 = x . . . . . . . use a calculator to do the multiplication
x ≈ 10.2 . . . . . . . . . . . round to the nearest tenth
Answer:
C and E
Step-by-step explanation:
-2/3 = -0.66
so hence forth
2/3 = 0.66
- (2/3) = -0.66 and
2/-3 = -0.66
For this case we have an equation of the form:
Where,
v0: initial value in assets
b: depreciation rate
t: time in years.
Substituting values we have:

For year 8 we have:

Rounding off we have:
V (t) = 83401
Answer:
the value of V0 and b are:
V0 = $ 408,000
b = 0.82
the value of the assets after 8 years is:V (t) = 83401 $
There are 18 packets.
Each packet has 10 cookies.
Let T = total number of cookies.
T = 10(18)
T = 180
There are 180 cookies.
Let C = cost of each cookie.
Use the equation C = 19.80/T.
You know what T is, right? Look above to see the value of T. Plug that T-value into the equation and solve for C.
After that, round your answer as instructed.