What is 10x5/6 pls helppp thank you

Mathematics

1 answer:

mote1985 [20]3 years ago

4 0

Answer:

The answer has many ongoing 3's so just shorten it to

8.3 or 8.33

You might be interested in

Can u help me on this plzz

avanturin [10]

Median: 29
Range: 25
IQR: 14.5

Explanations:

**Median:**
(To find the median, we need to first order all the elements)

Ordered —> 15, 18, 18, 20, 23, 28, 30, 33, 33, 34, 38, 40

(Since there are an even number of elements, we need to add the two elements in the middle and divide by 2)

Median = (28 + 30)/2 = 58/2 = 29

**Range:**

(To find the range, you just have the subtract the smallest one from the largest)

Range = 40 - 15 = 25

**IQR:**

First half of elements —> 15, 18, 18, 20, 23, 28
Second half of elements —> 30, 33, 33, 34, 38, 40

Q1 (Quartile 1) = Median of first half = (18 + 20)/2 = 38/2 = 19
Q3 (Quartile 3) = Median of second half = (33 + 34)/2 = 67/2 = 33.5

IQR = Q3 - Q1 = 33.5 - 19 = 14.5

5 0

2 years ago

40 points” help HLP HL

cestrela7 [59]

Answer:

D: {(-5, -4, 2, 2, 5)}

R: {(-6, 3, 4, 1, 5)}

The relation is NOT a function.

Step-by-step explanation:

By definition:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a relation in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).

Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).

Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.