In triangle ABC, angle A=40, angle C=70, and BC=8.5. To the nearest tenth, what is AB?

What is the correct answer of evaluate the expression 2 to the fifth power

ANEK [815]

2^5 = 2×2×2×2×2

= 4×2×2×2

=8×2×2

=16×2

=32

4 0

4 years ago

The following table shows the number of medals won in the 2008 Olympics for swimming by the top five countries. Country Number o

wariber [46]

Answer:

Of the total 31 + 20 + 6 + 6 + 6 = 69 medals, the USA won 31 of them. 31/69 as a percentage is about 45%. Since there are 360° in a full circle, 45% of that is 0.45 * 360 = 162°.

6 0

4 years ago

Special Triangles

Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = $\frac{\sqrt{3} }{2}$ and tan30° = $\frac{1}{\sqrt{3} }$ , then

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{m}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

$\sqrt{3}$ × m = 12 ( divide both sides by $\sqrt{3}$ )

m = $\frac{12}{\sqrt{3} }$ ← rationalise by multiplying numerator/ denominator by $\sqrt{3}$ )

m = $\frac{12}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{12\sqrt{3} }{3}$ = 4 $\sqrt{3}$

-------------------------------------------------------------------------------

tan30° = $\frac{opposite}{adjacent}$ = $\frac{n}{6}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

$\sqrt{3}$ × n = 6 ( divide both sides by $\sqrt{3}$ )

n = $\frac{6}{\sqrt{3} }$ ← rationalise the denominator

n = $\frac{6}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{6\sqrt{3} }{3}$ = 2 $\sqrt{3}$

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7 0

3 years ago

a point with a positive x-coordinate and a negative y- coordinate is reflected over the y-axis . what sentence will describe the

scoray [572]

Answer:

The sentence that describes the reflected point (x,-y) over the y-axis

Step-by-step explanation:

Since not sure if specific options are available lets answer this question in a general notation.

Let us consider the Co-ordinate system in two dimensions (i.e. and ); where the horizontal line represents the values and the vertical line representes the values.Now we are told that we have a point with a positive x-coordinate and a negative y-coordinate, thus:

This means our point is located at the 4th Quadrant (where values are positive and values are negative).

Reflecting it over the y-axis means that our point is now located on the 3rd Quadrant (where both and values are negative).

Therefore the new reflected point will now be:

''a point with a negative x-coordinate and a negative y-coordinate''

7 0

3 years ago

Can you help with this problem

Doss [256]

-1/2 I think...I hope I helped

6 0

3 years ago