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nataly862011 [7]
4 years ago
5

A line passes through the points (5,20) and ( 7 , 22). Write a linear function rule in terms of x and y for this line.

Mathematics
1 answer:
Sunny_sXe [5.5K]4 years ago
5 0

Answer:

<h2>y = x + 15</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (5, 20) and (7, 22). Substitute:

m=\dfrac{22-20}{7-5}=\dfrac{2}{2}=1

y-20=1(x-5)

y-20=x-5         <em>add 20 to both sides</em>

y=x+15

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1) Option A) is correct

The given rational exponent expression is not simplified correctly as a radical expression is

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2)Option A) is correct

That is (729x^3y^{-18})^{\frac{1}{6}}=\frac{3\sqrt{x}}{y^3}

Step-by-step explanation:

1) Given that x^{\frac{7}{4}}=(\sqrt{x^7})^\frac{1}{4}

x^{\frac{7}{4}}=\sqrt[4]{x^7} is the correct answer but in the given problem they gave the RHS as wrong.

Therefore the given rational exponent expression is not simplified correctly as a radical expression is

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2)Given that the rational exponent expression is (729x^3y^{-18})^{\frac{1}{6}}

To find it as a radical expression:

(729x^3y^{-18})^{\frac{1}{6}}=(729)^{\frac{1}{6}}(x^3)^{\frac{1}{6}}((y^{-18})^{\frac{1}{6}})

=3(x^{\frac{3}{6}})(y^{\frac{-18}{6}})

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Therefore Option A) is correct

That is (729x^3y^{-18})^{\frac{1}{6}}=\frac{3\sqrt{x}}{y^3}

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