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vampirchik [111]
3 years ago
13

In a lottery, 5000 tickets are sold for $1 each, one first prize of $2000, 1 second prize of $500, 3 third prizes of $100, and 1

0 consolation prizes of $25 are to be awarded. What are the expected net earnings of a person who buys one ticket?
Mathematics
1 answer:
RSB [31]3 years ago
4 0
There is 1/5000 chance to win first place of $2000,
1/5000 chance to win second place of $500
3/5000 chance to win third place of $100
10/5000 chance to win the consolation prize of $25.
The ticket costs $1.
We multiply each probability by the amount, and subtract the ticket cost, to get the expected net earnings:
(1/5000)($2000) + (1/5000)($500) + (3/5000)($100) + (10/5000)($25) - $1 = $(-0.39).
This means that there is an expected loss of $0.39.
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Answer:

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Step-by-step explanation:

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2 years ago
01:29:
ankoles [38]

Answer:

The length of arc LMN is 14.2cm

Step-by-step explanation:

First of all we have to calculate the circumference of the circle and then extract the portion that corresponds to MN

To solve this exercise we need to use the circumference formula of a circle:

c = circumference

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c = 2π * r

we replace the known values

c = 2 * 3.14 * 6cm

c = 37.68cm

As we know a circle is represented with 360 ° and they tell us that the angle of the MN part is 75 °, so we have to know the relationship with respect to the total

75° / 360° = 5/24

Now we multiply this number by the circumference and we will obtain the length of the arc MN

MN = 37.68cm * 5/24

MN = 7.85cm

Now we add the values ​​of LM with NM and we will obtain the length of LMN

LMN = 6.3cm + 7.85cm

LMN = 14.15cm

round to the nearest tenth

LMN = 14.15cm = 14.2cm

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