Question

Someone please help me out with this problem T-T I'm begging

Answer 1

Label the vertices of the quadrilateral A, B, C, D. Angle C is supplementary to the angle of measure 60 degrees, so its own measure is 120 degrees.

AD and BC are parallel, as are AB and CD, so ABCD is a parallelogram. This means angle A also has measure 120 degrees. The angle adjacent to the one with measure $3x$, part of angle A, then has measure $120^\circ-3x$.

The three angles above the line through vertex A are supplementary, so we have

$2x+90^\circ+(120^\circ-3x)=180^\circ$

$\implies210^\circ-x=180^\circ$

$\implies x=30^\circ$